Respuesta :

step 1

Find out the length side AC in the given right triangle

Applying the Pythagorean Theorem

[tex]\begin{gathered} 4^2=1^2+AC^2 \\ AC^2=4^2-1^2 \\ AC^2=15 \\ AC=\sqrt{15} \\ \end{gathered}[/tex]

so

sinA=1/4 ----> by SOH

cosA=√15/4 ----> by CAH

tanA=1/√15 ------> simplify -------> tanA=√15/15

cscA=1/sinA=4/1=4

secA=1/cosA=4/√15 -----> simplify ----> secA=4√15/15

cotA=√15/1=√15

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