Given
The diameter of the pulley is given as 20''.
The distance between two pulleys is 67''.
Explanation
To determine the total length of belting needed for the pulley .
Use the formula.
[tex]D=2L+(D_L+D_S)\times\frac{\pi}{2}+\frac{(D_L-D_S)^2}{4L}[/tex]
Here L is the distance between two pulleys and DL is the diameter of the larger pulley
DS is the diameter of the smaller pulley.
Substitute the values,
[tex]\begin{gathered} D=2\times67^{\prime}^{\prime}+(20^{\prime}^{\prime}+20^{\prime}^{\prime})\times\frac{\pi}{2}+\frac{(20^{\prime}^{\prime}-20^{\prime}^{\prime})^2}{4\times67^{\prime}^{\prime}} \\ D=134^{\prime}^{\prime}+40^{\prime}^{\prime}\times\frac{\pi}{2}+0 \\ D=134^{\prime}^{\prime}+62.8^{\prime}^{\prime} \\ D=196.8in \end{gathered}[/tex]Answer
Hence the total length of belting needed for the pulley is 196.8 in.
