Question

An inclined plane makes an angle of 30 degrees above the horizontal. If a block of 7 kg rests on the incline, what is the magnitude of the normal force that the incline exerts on the block?

Answer 1

Given data

*The given mass of the block is m = 7 kg

*The given angle is

$\theta=30^0$

The formula for the magnitude of the normal force that the inclined plane exerts on the block is given as

$f_n=mg\cos \theta$

Substitute the known values in the above expression as

$\begin{gathered} f_n=(7)(9.8)\cos 30^0 \\ =59.41\text{ N} \end{gathered}$

Hence, the magnitude of the normal force that the inclined plane exerts on the block is F_n = 59.41 N