Given:
The height of the cone, h=8 in.
The diameter of the base of the cone, D=3 in.
The radius of the cone is,
[tex]r=\frac{D}{2}=\frac{3}{2}=1.5\text{ in}[/tex]
The volume of the cone can be calculated as,
[tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ =\frac{1}{3}\times3\times1.5^2\times8 \\ =18in^3 \end{gathered}[/tex]
Therefore, the volume of the cone is 18 in^3.
