Given:
Point 1 ( -4, 1)
Point 2 ( 4, -3)
Required:
Point-slope form of the equation of the line
Solution:
[tex]y-y_1=m(x-x_1)[/tex][tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-3-1}{4-(-4)}=\frac{-4}{4+4_{}_{}}=\frac{-4}{8}=-\frac{1}{2}[/tex]
Point 1 ( -4, 1), m = -1/2
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-1=-\frac{1}{2}\lbrack x-(-4)\rbrack \\ y-1=-\frac{1}{2}(x+4) \end{gathered}[/tex]
Answer:
[tex]B)\text{ }y-1=-\frac{1}{2}(x+4)[/tex]
