[tex]\begin{gathered} x_1=8,x_2=-4,y_1=-9,y_2=15 \\ lin\text{e of equation is,} \\ (y-y_1)=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ (y-9)=\frac{15-(-9)}{-4-8}(x-8) \\ y-9=\frac{24}{-12}(x-8) \\ y-9=-2(x-8) \\ y-9=-2x+16 \\ y=-2x+9+16 \\ y=-2(x+8)-9 \\ y=-2(x+8)-9 \end{gathered}[/tex]