Answer:
b1 = (2A/h) - b2
Explanation:
The initial equation is:
[tex]A=\frac{1}{2}h(b_1+b_2)[/tex]
To solve for b1, multiply both sides by 2
[tex]\begin{gathered} 2\cdot A=2\cdot\frac{1}{2}h(b_1+b_2) \\ 2A=h(b_1+b_2) \end{gathered}[/tex]
Then divide both sides by h to get:
[tex]\begin{gathered} \frac{2A}{h}=\frac{h(b_1+b_2)}{h} \\ \frac{2A}{h}=b_1+b_2 \end{gathered}[/tex]
Now, subtract b2 from both sides:
[tex]\begin{gathered} \frac{2A}{h}-b_2=b_1+b_2-b_2 \\ \frac{2A}{h}-b_2=b_1 \end{gathered}[/tex]
Therefore, the solution is:
[tex]b_1=\frac{2A}{h}-b_2[/tex]
