1) Based on this formula:
[tex]I=Prt[/tex]2) We can solve for r, this way:
[tex]\begin{gathered} I=Prt \\ \\ Prt=I \\ \\ \frac{Prt}{Pt}=\frac{I}{Pt} \\ \\ r=\frac{I}{Pt} \end{gathered}[/tex]3) We can solve this question, by plugging into the formula the given data and solving it for "r"
3000 dollars are invested at a simple interest rate of 4 percent for 5 years. How much interest is earned, to the nearest cent?
______ dollars
[tex]\begin{gathered} I=Prt \\ \\ I=3000\times0.04\times5 \\ \\ I=600 \end{gathered}[/tex]4) For the following question:
What is the interest rate, as a percent, that is necessary to earn 300 dollars in simple interest if 2000 dollars are invested for 2 years, to 1 decimal place?
_____ % year
[tex]\begin{gathered} I=Prt \\ \\ 300=2000\times r\times2 \\ \\ 300=400r \\ \\ \frac{300}{400}=\frac{400r}{400} \\ \\ r=\frac{3}{4}=0.75=75\% \end{gathered}[/tex]