Solve the right triangle using the given information. a = 77.7 yd, b = 42.7 yd B A= degrees minutes B = degrees minutes yd (round to the nearest tenth)

ok, from pythagoras theorem,
[tex]c^2=a^2+b^2[/tex][tex]c^2=77.7^2+42.7^2=7860.58yd^2[/tex][tex]c=88.66\text{ yd}[/tex]c= 88.7 yards, to the nearest tenth
[tex]\begin{gathered} A=\sin ^{-1}(\frac{77,7}{88.7})=61^{\circ\text{ }}9.66\text{ minutes} \\ B=\sin ^{-1}\frac{42.7}{88.7}=48^{\circ}\text{ 46.8 minutes} \end{gathered}[/tex]