Question

A(n)=-9+(n-1)(6) find the third and 13th term of sequence

Answer 1

The recursive formula is:

$A(n)=-9+(n-1)(6)$

Where n is the n'th term

Third term:

Put n = 3, so we have:

$\begin{gathered} A(3)=-9+(3-1)(6) \\ =-9+(2)(6) \\ =3 \end{gathered}$

Thirteenth term:

Put n = 13, so we have:

$\begin{gathered} A(13)=-9+(13-1)(6) \\ =-9+(12)(6) \\ =63 \end{gathered}$