Helen made an error whe she expressed the factor 2^4/3 in radical form. The correct expression is:
[tex]2^{\frac{4}{3}}=\sqrt[3]{2^4}=\sqrt[3]{8}[/tex]
Then, the simplified expression is:
[tex]\frac{\sqrt[3]{8}}{e}[/tex]
Stephen made an error when he write ln2 as simply 2, in the second step. The correct procedure is:
[tex]e^{\frac{4}{3}ln2-1}=e^{\frac{4}{3}\ln 2}\cdot e^{-1}=^{}2^{\frac{4}{3}}\cdot e^{-1}=\frac{\sqrt[3]{8}}{e}[/tex]
