We can find the value of x, using the law of cosines:
[tex]\begin{gathered} a^2=b^2+c^2-2bc\cos (\alpha) \\ _{\text{ }}where\colon \\ a=x \\ b=320 \\ c=112 \\ \alpha=130 \end{gathered}[/tex]
Therefore:
[tex]x=(320)^2+112^2-2(320)(112)\cos (130)[/tex][tex]x\approx401[/tex]
Answer:
401 mi
