Question

Graph the line that passes through the points (6,3) and (2,3) and determine the equation of the line.

Answer 1

Consider that the equation of the line is given by:

y = mx + b

where m is the slope of the line and b the y-intercept.

the slope m is calculated by using the following formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

where (x1,y1) and (x2,y2) are two points on the line.

In this case, we have:

(x1,y1) = (2,3)

(x2,y2) = (6,3)

By replacing we get:

$m=\frac{3-3}{6-2}=0$

Now, take into account that the slope is 0, which means that the line is horizontal with y-intercept (0,3).

The graph is shown below:

the equation of the line is y = 3