We will determine the values of b & c as follows:
*First: We remember both equation forms:
*General form:
[tex]f(x)=ax^2+bx+c[/tex]
*Vertex form:
[tex]f(x)=a(x-h)^2+k[/tex]
Here (h, k) is the vertex.
Then we will proceed from the vertex from to the general form and solve for b & c:
[tex]f(x)=20(x-6)^2-2\Rightarrow f(x)=20(x^2-12x+36)-2[/tex][tex]\Rightarrow f(x)=20x^2-240x+718[/tex]
Then:
[tex]\begin{cases}b=-240 \\ c=718\end{cases}[/tex]
This, can be seen as follows:
