Question

what is the percent of n in Li3N [li=6.94 amu, n=14.01 amu]

Answer 1

The percent of N in Li3N is 40.22%.

- First, we need to calculate the molar mass of Li3N:

$\begin{gathered} Li=\text{ 6.94 amu} \\ \text{Li x 3= 20.82} \\ N=14.01\text{ amu} \\ Li_3N=34.83\text{ g/mole} \end{gathered}$

So, the molar mass of Li3N is 34.83 g/mole.

- Second, we calculate the percent of N in the molecule of Li3N:

$\frac{14.01\cdot100}{34.83}=40.22$

So, the percent of N in Li3N is 40.22%.