we have the equation
[tex]\frac{x}{4}+\frac{x}{3}=\frac{7}{12}[/tex]Solve for x
Multiply on both sides by 12 to remove the fractions
[tex]\begin{gathered} \frac{x}{4}*12+\frac{x}{3}*12=\frac{7}{12}*12 \\ \\ 3x+4x=7 \\ combine\text{ like terms} \\ 7x=7 \\ Divide\text{ by 7 on both sides} \\ x=1 \end{gathered}[/tex]Check the answer
Substitute the value of x in the original equation
[tex]\begin{gathered} \frac{x}{4}+\frac{x}{3}=\frac{7}{12} \\ \\ \frac{1}{4}+\frac{1}{3}=\frac{7}{12} \\ Multiply\text{ by 12 on both sides} \\ \frac{1}{4}*12+\frac{1}{3}*12=\frac{7}{12}*12 \\ 3+4=7 \\ 7=7\text{ is ok} \end{gathered}[/tex]
