Respuesta :

To answer this question, we can use the substitution method or the elimination method.

If we use the substitution method, we can proceed as follows:

1. Solve the first equation for x:

[tex]x-5y=2[/tex]

If we add 5y to both sides of the equation, we have:

[tex]x-5y+5y=2+5y\Rightarrow x=2+5y[/tex]

2. We can substitute the corresponding value of x - as a function of y - as follows:

[tex]2(2+5y)+y=4[/tex]

3. Now, we can solve the equation for y as follows:

a. Apply the distributive property:

[tex]2\cdot2+2\cdot5y+y=4\Rightarrow4+10y+y=4[/tex]

b. Adding like terms, and subtracting 4 from both sides:

[tex]4+11y=4\Rightarrow4-4+11y=4-4\Rightarrow11y=0\Rightarrow y=0[/tex]

4. If we substitute this value for y in the first equation, we will have:

[tex]x-5(0)=2\Rightarrow x=2[/tex]

Therefore, we have that the solution for this system of linear equations is x = 2, and y = 0.

We can check these results, if we substitute those values into the original equations:

x = 2

y = 0

[tex]2-5(0)=2\Rightarrow2=2[/tex][tex]2(2)+0=4\Rightarrow4=4[/tex]

In summary, we have that the solution to the system of equations is:

x = 2 and y = 0.

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