You can use the following formula in order to calculate the Lateral area of the right cylinder given in the exercise:
[tex]LA=2\pi rh[/tex]
Where "LA" is the lateral area of the cylinder, "r" is the radius and "h" is the height.
In this case you know that its diameter is:
[tex]d=6.4yd[/tex]
Since the diameter of a circle is twice the radius:
[tex]2r=6.4yd[/tex]
Knowing that the height of the cylinder is:
[tex]h=16.2yd[/tex]
You can substitute values into the formula and then evaluate, in order to find the lateral area:
[tex]\begin{gathered} LA=\pi(6.4yd)(16.2yd) \\ LA\approx325.7yd^2 \end{gathered}[/tex]
Then, the answer is:
[tex]LA\approx325.7yd^2[/tex]
