We are required to calculate mass of calcium nitrate, given the following balanced equation:
[tex]\text{Ca(NO}_3)_2\text{ + }2\text{HCl}\rightarrow CaCl_2\text{ + }2HNO_3[/tex]
Given:
moles of HCl = 2 mol
We can use the stoichiometry to calculate the moles of Ca(NO3)2.
The molar ratio between HCl and Ca(NO3)2 is 1:2
Therefore the number of moles of Ca(NO3)2 = 2 x (1/2) = 1.00 mol
Now that we do have the number of moles we can calculate the mass.
n = m/M
m = n x M
m = 1.00 x 164.09
m = 164 g
Therefore the answer is the last one.
