Question

pretty sure answer is 37 degrees just want a quick check to be sure

Answer 1

Given :

$\begin{gathered} AD\parallel BC \\ EB\parallel DC \\ \angle BAE=90^{\circ} \\ \angle ABE=53^{\circ} \end{gathered}$$\begin{gathered} \Delta ABE \\ \angle AEB+\angle EAB+\angle EBA=180^{\circ} \\ \angle AEB+90^{\circ}+53^{\circ}=180^{\circ} \\ \angle AEB=180^{\circ}-143^{\circ} \\ \angle AEB=37^{\circ} \end{gathered}$

AS EB is parallel to DC

From corresponding angles

$\begin{gathered} \angle AEB=\angle EDC \\ =37^{\circ} \end{gathered}$

Thus, the required value of angle is 37.