Question

Match the formula used to find the area to each image.4 ft

Answer 1

Solution:

Given:

$\begin{gathered} The\text{ first image is a parallelogram;} \\ Area\text{ of parallelogram}=base\times height \\ A=bh \\ where: \\ b=18 \\ h=15 \\ A=18\times15 \\ A=270in^2 \end{gathered}$

$\begin{gathered} The\text{ second image is a rhombus} \\ Area\text{ of rhombus}=\frac{pq}{2}=\frac{d_1d_2}{2} \\ where: \\ d_1=diagonal\text{ 1}=12cm \\ d_2=diagonal\text{ 2}=8cm \\ A=\frac{12\times8}{2} \\ A=\frac{96}{2} \\ A=48cm^2 \end{gathered}$

$\begin{gathered} The\text{ third image is a trapezoid.} \\ A=\frac{(b_1+b_2)h}{2} \\ where: \\ b_1=4in \\ b_2=6in \\ h=3in \\ A=\frac{(4+6)}{2}\times3 \\ A=\frac{10}{2}\times3 \\ A=5\times3 \\ A=15in^2 \end{gathered}$

Therefore, the formula used to find the area of each image is;