Question

What is the probability of not getting an even number on the spinner?A.2/6 B.3/6C.2/3D.5/6

Answer 1

Given:

Spinner with number in it 1, 2, 3, 4, 5 and 7.

To find:

Probability of not getting even number.

Explanation:

Probability of event happening

$=\frac{favorable\text{ cases }}{total\text{ cases}}$

P(event not happening)=1-P(event happening)

Solution:

We have 2, 4 are the even numbers out of 6 numbers.

So,

$\begin{gathered} P=\frac{2}{6} \\ =\frac{1}{3} \end{gathered}$

Now,

$\begin{gathered} \bar{P}=1-\frac{1}{3} \\ =\frac{2}{3} \end{gathered}$

So, probability of not getting even number is 2/3.