The figure has the following points
[tex]\begin{gathered} \text{target T} \\ T(6,2) \\ \text{Mcdonald D} \\ D(1,4) \\ \text{Sam CLub S} \\ S(6,6) \end{gathered}[/tex]
In other to get the distance between McDonald's and Sam Club using Pythagoras theorem
Let the distance between Mcdonald and Sam Club be MS, it follows that
[tex]\begin{gathered} MC^2=5^2+2^2 \\ MC^2=25+4 \\ MC^2=29 \\ MC=\sqrt[]{29} \\ MC=5.385 \end{gathered}[/tex]
a) Hence, the distance between Mcdonald's and Sam Club is 5.385
b) To get the distance between Mcdonald's and Target using the distance formula
The distance formula is given as
[tex]\begin{gathered} A(x_1,y_1);B(x_2,y_2) \\ AB=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \end{gathered}[/tex]
[tex]\begin{gathered} M(1,4) \\ T(6,6) \\ MT=\sqrt[]{(6-4)^2+(6-1)^2} \\ MT=\sqrt[]{2^2+5^2} \\ MT=\sqrt[]{4+25} \\ MT=\sqrt[]{29} \\ MT=5.385 \end{gathered}[/tex]
b) Hence, the distance between Mcdonald's and Target using the distance formula is 5.385
c) The midpoint formula is given as
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
The midpoint of between McDonald's and Sam Club is
[tex]\begin{gathered} M(1,4);S(6,6)^{} \\ \text{midpoint}=(\frac{6+1}{2},\frac{6+4}{2}) \\ =(\frac{7}{2},\frac{10}{2}) \\ =(\frac{7}{2},5) \end{gathered}[/tex]
Hence, the midpoint between McDonald's and Sam Club is (7/2,5)
