Question

how would I find the area of a trapezoid whose bases are x and 3x+4 and height is x+2

Answer 1

Area of Trapezium.

By formula,

$\begin{gathered} \text{Area =}\frac{1}{2}(a\text{ + b)h} \\ \text{Where a =x , b = 3x+4 , and h = x + 2} \\ \text{Area =}\frac{1}{2}(x+3x+4)(x+2) \\ \text{Area =}\frac{1}{2}(4x+4)(x+2) \\ \\ \text{Area = }\frac{1}{2}\times4(x+1)(x+2)\text{ =2(x+1)(x+2)} \end{gathered}$

So, the correct answer is 2(x+1)(x+2)