Question

Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=11x−3 and CE=12−4x. Find x.A. 18B. 8C. 1D. 16

Answer 1

SOLUTION

Now, let us draw the diagram of the parallelogram

From the image above, E is the mid-point of the line AC.

This means that AE = CE. From here we have that

$11x-3=12-4x$

Now we can find x. This becomes

$\begin{gathered} 11x-3=12-4x \\ \\ 11x+4x=12+3 \\ \\ 15x=15 \\ \\ x=\frac{15}{15} \\ \\ x=1 \end{gathered}$

So, the correct answer is option C.