Solution:
Given that;
A bag contains 8 tiles labeled A, B, C, D, E, F, G and H
Total tiles = 8
The vowels in the bag is A and E
Let V represent vowels
[tex]nP(V)=2[/tex]
The probability of a vowel is
[tex]\begin{gathered} P=\frac{2}{8}=\frac{1}{4} \\ P=\frac{1}{4} \end{gathered}[/tex]
Hence, the answer is 1/4
