Solution
Step 1
Y is inversely proportional to the square root of x.
[tex]y\text{ = }\frac{k}{x^2}[/tex]Step 2
Find the value of k if Y = 9 when x = 2.
[tex]\begin{gathered} y\text{ = }\frac{k}{x^2} \\ \\ 9\text{ = }\frac{k}{2^2} \\ \\ k\text{ = 9}\times4\text{ = 36} \end{gathered}[/tex]Step 3
What is Y, when x is 10?
[tex]\begin{gathered} y\text{ = }\frac{36}{10^2} \\ \\ y\text{ = }\frac{36}{100} \\ \\ y\text{ = }\frac{9}{25} \end{gathered}[/tex]Final answer
[tex]\frac{9}{25}[/tex]