Respuesta :

Solution

Step 1

Y is inversely proportional to the square root of x.

[tex]y\text{ = }\frac{k}{x^2}[/tex]

Step 2

Find the value of k if Y = 9 when x = 2.

[tex]\begin{gathered} y\text{ = }\frac{k}{x^2} \\ \\ 9\text{ = }\frac{k}{2^2} \\ \\ k\text{ = 9}\times4\text{ = 36} \end{gathered}[/tex]

Step 3

What is Y, when x is 10?

[tex]\begin{gathered} y\text{ = }\frac{36}{10^2} \\ \\ y\text{ = }\frac{36}{100} \\ \\ y\text{ = }\frac{9}{25} \end{gathered}[/tex]

Final answer

[tex]\frac{9}{25}[/tex]

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