Question

2.A 46.5 L tank of ammonia has a pressure of 16.7 kPa. Calculatethe volume of the ammonia if its pressure is changed to 9.1 kPa.

Answer 1

Answer:

The volume is 85.34L.

Explanation:

1st) To calculate the volume, we can use the Boyle's Law:

$P_1*V_1=P_2*V_2$

The given information in the exercise is:

- V1: 46.5L

- P1: 16.7kPa

- P2: 9.1kPa

- V2: this is what we have to calculate.

2nd) Replacing the values in the formula:

$\begin{gathered} P_1*V_1=P_2*V_2 \\ 16.7kPa*46.5L=9.1kPa*V_2 \\ 776.55kPa*L=9.1kPa*V_2 \\ \frac{776.55kPa*L}{9.1kPa}=V_2 \\ 85.34L=V_2 \end{gathered}$

So, the volume of the ammonia is 85.34L.