First, we multiply the 2nd equation by (2). We have:
[tex]\begin{gathered} 2\times\lbrack5x-2y=18\rbrack \\ 10x-4y=36 \end{gathered}[/tex]Now, we have:
[tex]\begin{gathered} 3x+4y=-10 \\ 10x-4y=36 \end{gathered}[/tex]We add both equations and solve for x. Shown below:
[tex]\begin{gathered} 3x+4y=-10 \\ 10x-4y=36 \\ ----------- \\ 13x=26 \\ x=\frac{26}{13} \\ x=2 \end{gathered}[/tex]AnswerA