Answer:
a. 148.1 (g).
Explanation:
What is given?
Volume of solution = 575.9 mL = 0.5759 L,
Molarity of solution = 1.6114 M,
Molar mass of CuSO4 = 159.5 g/mol.
Step-by-step solution:
To find the mass of CuSO4 in the solution, we have to use the molarity formula:
[tex]Molarity\text{ \lparen M\rparen=}\frac{moles\text{ of solute}}{liters\text{ of solution}}=\frac{mol}{L}.[/tex]Let's solve for 'moles of solute', and replace the given data (remember that the volume must be in liters), like this:
[tex]\begin{gathered} Moles\text{ of solute=molarity}\cdot liters\text{ of solution,} \\ \\ Moles\text{ of solute=1.6114 M}\cdot0.5759\text{ L,} \\ \\ Moles\text{ of solute}=0.928\text{ moles.} \end{gathered}[/tex]The final step is to convert 0.928 moles of CuSO4 to grams using the molar mass of CuSO4, as follows:
[tex]0.928\text{ moles CuSO}_4\cdot\frac{159.5\text{ g CuSO}_4}{1\text{ mol CuSO}_4}=148.02\text{ g.}[/tex]The answer would be the nearest to 148.02 g, which is a. 148.1 (g).
