Giving the function
[tex]f(x)=x^2+6x+1[/tex]the vertex is giving by
[tex]h=\frac{-b}{2a}[/tex]where
a=1
b=6
c=1
then
[tex]h=\frac{-6}{2*1}[/tex][tex]h=\frac{-6}{2}=-3[/tex]then
[tex]f(-3)=-3^2+6(-3)+1[/tex][tex]f(-3)=9-18+1[/tex][tex]f(-3)=-8[/tex]then the vertex is in the point
(-3,-8)
