A gas is in a sealed balloon is held under isobaric conditions. The initial temperature is 20.Ā°C and the volume is 10.0 L. If the balloon expands to 15.0L, what is the final temperature in Ā°C?

Respuesta :

Answer

The final temperature in Ā°C = 166.6 Ā°C.

Explanation

Given:

Initial temperature, Tā‚ = 20.0 Ā°C

Initial volume, Vā‚ = 10.0 L

Final volume, Vā‚‚ = 15.0 L

What to find:

The final temperature in Ā°C.

Step-by-step solution:

Since is held under isobaric conditions i.e constant pressure, the final temperature can be determined using the Charle's law equation below.

[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \\ \Rightarrow T_2=\frac{T_1V_2}{V_1} \end{gathered}[/tex]

Plugging Tā‚ = (20.0 + 273.15) = 293.15 K, Vā‚ = 10.0 L and Vā‚‚ = 15.0 L into the equation, we have

[tex]T_2=\frac{293.15\text{ }K\times15.0\text{ }L}{10.0\text{ }L}=439.725K[/tex]

The final step is to convert the temperature from Kelvin to Ā°C.

The final temperature = (439.725 - 273.15) = 166.6 Ā°C.

ACCESS MORE
EDU ACCESS
Universidad de Mexico