Question

Please help me with this problem I have been working on it but I keep getting it wrong this is my finale try please help.Solve for b. a = 9b²cA. b=±a√3cB. b=±ac√9C. b=±ac√3c D. b=±3ac−−√

Answer 1

To answer this question, we have to follow the next steps:

1. We have:

$a=9b^2c$

2. Divide both sides by 9c:

$\begin{gathered} \frac{a}{9c}=\frac{9b^2c}{9c}=\frac{9c}{9c}b^2 \\ \frac{a}{9c}=b^2 \end{gathered}$

3. Take the square root to both sides as follows:

$\begin{gathered} \frac{a}{9c}=b^2 \\ b^2=\frac{a}{9c} \\ \sqrt[]{b^2}=\pm\sqrt[]{\frac{a}{9c}} \\ \\ \\ \\ \end{gathered}$