Question

What volume of 0.46M NaOH is required to neutralize 50.0 mL of 0.31 M OF of HNO3

Answer 1

Answer

33.7 mL of NaOH

Explanation

Given:

Molarity of NaOH = 0.46 M

Molarity of HNO3 = 0.31 M

Volume of HNO3 = 50.0 mL

What to find:

The volume of NaOH.

Step-by-step solution:

The equation for the reaction is:

NaOH + HNO3 → NaNO3 + H2O

Mole ratio of NaOH to HNO3 is 1:1

The volume of NaOH can be calculated using:

$\begin{gathered} \frac{C_aV_a}{n_a}=\frac{C_bV_b}{n_b} \\ \\ \frac{0.31M\times50.0mL}{1}=\frac{0.46M\times V_b}{1} \\ \\ V_b=\frac{0.31M\times50.0mL}{0.46M} \\ \\ V_b=33.7\text{ }mL \end{gathered}$

Hence, 33.7 mL of 0.46M NaOH is required to neutralize 50.0 mL of 0.31 M OF of HNO3