Respuesta :

To answer this question first we need to set our parental relationships as follows:

Secondly, we set our characteristic of interest, in this case Curly/straight hair

Alleles

Dominant: C= Curly hair

Recessive: c= straight hair

Then we set our inheritance of traits, therefore it will be as follows

Now we can proceed to do our punnet squares

P: Cc x Cc

Apply for: Kate x Jayden and Fred x Brittney

[tex]\begin{bmatrix}{\placeholder{⬚}} & {C} & {c} \\ {C} & {CC} & {Cc} \\ {c} & {Cc} & {cc}\end{bmatrix}[/tex]

Frequencies:

Genotypic: CC (1/4), Cc(2/4), cc(1/4)

Phenotypic: Curly hair (3) straight hair (1)

P: Cc x cc

Apply for: Jimmy x Ara

[tex]\begin{bmatrix}{\placeholder{⬚}} & {C} & {c} \\ {c} & {Cc} & {cc} \\ {c} & {Cc} & {cc}\end{bmatrix}[/tex]

Frequencies:

Genotypic: Cc (2/4), cc(2/4)

Phenotypic: Curly hair (2) Straight hair (2)

P: Cc x CC

Apply for: Brooklyn x Timmy

[tex]\begin{bmatrix}{\placeholder{⬚}} & {C} & {C} \\ {C} & {CC} & {CC} \\ {c} & {Cc} & {Cc}\end{bmatrix}[/tex]

Frequencies

Genotypic: CC (2/4), Cc (2/4)

Phenotypic: Curly hair (4/4)

Ver imagen GwynevereZ649226
Ver imagen GwynevereZ649226
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