Question

The equation of a line is given below.- 6x + 3y=12Find the slope and the v-intercept.Then use them to graph the line.

Answer 1

We have a equation of a line and want to find the slope and the interception with the y-axis.

We need to write our equation in the form:

$y=m\cdot x+b$

Where m is the slope and b is the y-intercept value.

So,

$\begin{gathered} -6x+3y=12 \\ 3y=6x+12 \\ y=\frac{6x+12}{3} \\ y=\frac{6}{3}x+\frac{12}{3} \\ y=2x+4 \end{gathered}$

So the slope m=2 and the y-intercept is b=4.

A graph of the line will be: