I need help finding the missing length with a radical form as an answer! I will provide the full photo

By Trigonometric Ratio,
[tex]\begin{gathered} \tan 60=\frac{2}{y} \\ \text{Cross multiply to get,} \\ y=\frac{2}{\tan 60} \\ y=\frac{2}{\sqrt[]{3}} \\ y=\frac{2\text{ }\sqrt[]{3}}{\sqrt[]{3}\text{ }\times\sqrt[]{3}} \\ y=\frac{2\sqrt[]{3}}{3} \\ y=\frac{2}{3}\text{ }\sqrt[]{3} \end{gathered}[/tex]To find the value of x :
[tex]\begin{gathered} \sin 60=\frac{2}{x} \\ \text{Cross multiplying, we get,} \\ x=\frac{2}{\sin 60} \\ \\ x=\frac{2}{\frac{\sqrt[]{3}}{2}}=\frac{4}{\sqrt[]{3}} \\ \\ x=\frac{4\sqrt[]{3}}{\sqrt[]{3}\times\sqrt[]{3}} \\ \\ x=\frac{4\text{ }\sqrt[]{3}}{3} \end{gathered}[/tex]