Respuesta :

ANSWER :

x = 3

EXPLANATION :

From the problem, we have the equation :

[tex]\log_7(5x+12)=\log_7(3x+18)[/tex]

Since we have two logarithms both having the same base of 7, we can equate it by :

[tex]\begin{gathered} \operatorname{\log}_{7}(5x+12)=\operatorname{\log}_{7}(3x+18) \\ 5x+12=3x+18 \end{gathered}[/tex]

Solve for the value of x :

[tex]\begin{gathered} 5x+12=3x+18 \\ 5x-3x=18-12 \\ 2x=6 \\ x=\frac{6}{2} \\ x=3 \end{gathered}[/tex]

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