First we solve the expression in the parenthesis:
[tex]3^{\frac{2}{3}^{}}=\sqrt[3]{3^2}\text{ = }\sqrt[3]{9}[/tex][tex]\begin{gathered} \sqrt[3]{9}=9^{\frac{1}{3}} \\ (3^{\frac{2}{3}})^{\frac{1}{6}}\text{ }=(9^{\frac{1}{3}})^{\frac{1}{6}} \\ =9^{\frac{1}{3}\times\frac{1}{6}} \end{gathered}[/tex][tex]\begin{gathered} =9^{\frac{1}{18}}=3^{2\times\frac{1}{18}} \\ =3^{\frac{2}{18}}=3^{\frac{1}{9}} \\ 9^{\frac{1}{3}}=\sqrt[9]{3} \end{gathered}[/tex]