Question

A horizontal force of 30 N just starts to move a 9kg object. Findthe value of coefficient of static friction and angle of friction.

Answer 1

Use the static friction formula.

$\begin{gathered} \mu_s=\frac{F}{mg}=\frac{30N}{9\operatorname{kg}\cdot9.8\cdot\frac{m}{s^2}} \\ \mu_s=0.34 \end{gathered}$

Therefore, the coefficient of static friction is 0.34. The angle of friction would be 180 because it's opposite to the direction of the movemNo ent.