Answer: [tex]\begin{gathered} 7^{-2} \\ first\text{ blank = 7} \\ second\text{ blank \lparen exponent\rparen = -2} \end{gathered}[/tex]
Explanation:
Given:
[tex]\frac{1}{49}[/tex]
To find:
to write the number with a negative exponent
[tex]\begin{gathered} 49\text{ is a perfect square} \\ 49\text{ = 7}^2 \\ \\ \frac{1}{49}\text{ = }\frac{1}{7^2} \end{gathered}[/tex][tex]\begin{gathered} writing\text{ the expression in the form of a negative exponent:} \\ \frac{1}{a^b}\text{ = a}^{-b}\text{ \lparen one of the exponent rules\rparen} \\ \\ \frac{1}{7^2}\text{ = 7}^{-2} \end{gathered}[/tex]
