Question

A ceramic container used for melting metals (called a crucible) contains 1.30 kg of a molten metal. The liquid metal cools until it reaches its melting point of 1,749°C. A scientist then measures that 2.99 ✕ 104 J of heat is transferred out of the metal before it completely solidifies. What is the latent heat of fusion of this metal, in J/g? (Be careful with units!) answer in J/g

Answer 1

Answer:

23 j / g

Explanation:

The latent heat of fusion is the amount of energy required to either melt or solidfiy a gram of a material at its melting point.

We know that 2.99 * 10^4 J are required to solidify 1.30 kg ( or 1300 g) of the metal; therefore, the latent heat is

$L=\frac{2.99\times10^4J}{1300g}23J/g$

which is our answer!

Hence, the latent heat of fusion for the metal is 23 J/g.