Remember that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
P=(700+250+400+1,500)=$2,850
n=365
r=4%=0.04
t=36 months=3 years
substitute in the formula
[tex]\begin{gathered} A=2,850(1+\frac{0.04}{365})^{365\cdot3} \\ A=\$3,213.34 \end{gathered}[/tex]