Answer:
0.16 moles of KClO4 are produced.
Explanation:
1st) According to the balanced reaction 4 moles of KClO3 produces 3 moles of KClO4.
With the KClO3 molar mass (122.55g/mol) we can convert the 4 moles into grams:
[tex]4moles*\frac{122.55g}{1mole}=490.2g[/tex]2nd) Finally, we can calculate the moles of KClO4 that will be produced from 26 grams of KClO3:
[tex]\begin{gathered} 490.2gKClO_3-3molesKClO_4 \\ 26gKClO_3-x=\frac{26gKClO_3*3molesKClO_4}{490.2gKClO_3} \\ x=0.16molesKClO_4 \end{gathered}[/tex]So, 0.16 moles of KClO4 are produced.