Question

How do you solve this problem? Not used to one with a fraction

Answer 1

$\frac{2}{3}x-2\ge0$

Solve for x:

Multiply both sides by 3:

$\begin{gathered} 3(\frac{2}{3}x-2)\ge0 \\ 2x-6\ge0 \end{gathered}$

Add 6 to both sides:

$\begin{gathered} 2x-6+6\ge0+6 \\ 2x\ge6 \end{gathered}$

Divide both sides by 2:

$\begin{gathered} \frac{2x}{2}\ge\frac{6}{2} \\ x\ge3 \end{gathered}$