Question

The image of K' after a dilation of 6 is (24, 42). What was K?

Answer 1

The dilation multiplies the coordinates of a point by a specific value.

If the point K' (24,42) was dilated by a factor of 6, in order to find the original point K, we just need to divide the coordinates of K' by 6. So we have that:

$K^{\prime}(24,42)\to K(\frac{24}{6},\frac{42}{6})=K(4,7)$

So the coordinates of K are (4, 7)