Find the area of the followingrhombus:2m13 mA = [?] m²

We can see that the rhombus is composed of 4 congruent right triangles. The area of a triangle is:
[tex]Area\text{ }triangle=\frac{b\cdot h}{2}[/tex]Where:
b is the base of the triangle
h is the height of the triangle
If the rhombus is composed of 4 identical right triangles, then the area of the rhombus is:
[tex]Area\text{ }rhombus=4\cdot Area\text{ }triangle=4\cdot\frac{b\cdot h}{2}=2bh[/tex]Thus, the area of the rhombus is twice the height times the base.
We can see in the figure that:
b = 13m
h = 2m
Then, we can write:
[tex]Area\text{ }rhombus=2\cdot13m\cdot2m=52m^m[/tex]Thus, the answer is:
[tex]A=52m^2[/tex]