The equation of the line is:
[tex]y=\dfrac{3}{5}x-\dfrac{26}{5}[/tex]
We are asked to find the equation of a line that pass through (2,-4) and having a slope of 3/5.
We know that the equation of a line with slope m and passing through points (a,b) is:
[tex]y-b=m(x-a)[/tex]
Here (a,b)=(2,-4) and m=3/5
Hence, the equation of line is:
[tex]y-(-4)=\dfrac{3}{5}\times (x-2)\\\\i.e.\\\\y+4=\dfrac{3}{5}\times (x-2)\\\\i.e.\\\\y=\dfrac{3}{5}x-\dfrac{6}{5}-4\\\\i.e.\\\\y=\dfrac{3}{5}x-\dfrac{26}{5}[/tex]