Explanation:
The mole
Percent composition
----
Data provided:
The molecular weight of C = 12.0107 g/mol
The molecular weight of C10H14 = 10 x 12.0107 + 14 x 1.00794 = 134.218 g/mol
---
Procedure:
% by mass of C:
[tex]\text{ \%by mass = }\frac{10\text{ x 12.0107 g/mol }}{134.218\text{ g/mol}}x100\text{ = 89.4865 \%}[/tex]
Answer: 89.4865 %
