If (x, 0) lies on the graph of y = log b x then x =

Given:-
[tex]y=log_b(x)[/tex]To find the value of x when the point is (x,0).
So now we substitute the point. so we get,
[tex]0=log_b(x)[/tex]So now we simplify using log formula and we get,
[tex]\begin{gathered} log^{-1}(0)=x \\ 1=x \end{gathered}[/tex]So the value of x is 1.